10=7x+2[3(1-x)-2(1+x)]

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Solution for 10=7x+2[3(1-x)-2(1+x)] equation:


Simplifying
10 = 7x + 2[3(1 + -1x) + -2(1 + x)]
10 = 7x + 2[(1 * 3 + -1x * 3) + -2(1 + x)]
10 = 7x + 2[(3 + -3x) + -2(1 + x)]
10 = 7x + 2[3 + -3x + (1 * -2 + x * -2)]
10 = 7x + 2[3 + -3x + (-2 + -2x)]

Reorder the terms:
10 = 7x + 2[3 + -2 + -3x + -2x]

Combine like terms: 3 + -2 = 1
10 = 7x + 2[1 + -3x + -2x]

Combine like terms: -3x + -2x = -5x
10 = 7x + 2[1 + -5x]
10 = 7x + [1 * 2 + -5x * 2]
10 = 7x + [2 + -10x]

Reorder the terms:
10 = 2 + 7x + -10x

Combine like terms: 7x + -10x = -3x
10 = 2 + -3x

Solving
10 = 2 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
10 + 3x = 2 + -3x + 3x

Combine like terms: -3x + 3x = 0
10 + 3x = 2 + 0
10 + 3x = 2

Add '-10' to each side of the equation.
10 + -10 + 3x = 2 + -10

Combine like terms: 10 + -10 = 0
0 + 3x = 2 + -10
3x = 2 + -10

Combine like terms: 2 + -10 = -8
3x = -8

Divide each side by '3'.
x = -2.666666667

Simplifying
x = -2.666666667

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